Question

find the area of a quadrant of a circle whose circumference is 22cm? ​

Answer 1

Answer:

Formulas used =

1. Circumference = 2 pie r

2. Area of Quadrant = 1/4 Pie r²

Circumference = 2 Pie r

22 = 2 * 22/7 r

r = 22 * 7 / 22 * 2

r = 7/2 or 3.5 cm

Area Of Quadrant = 1/4 Pie r²

= (1/4) * (22/7 ) * 3.5 * 3.5

= 1 * 22 * 35 * 35 / 4 * 7 * 10 * 10

= 1 * 11 * 35 / 4 * 10

= 9.625 cm²

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Answer 2

$\Large{\underline{\underline{\mathfrak{AnSwEr :}}}}$

$\sf{\dashrightarrow Circumference = 2 \pi r} \\ \\ \sf{\dashrightarrow 22 = 2 \times \dfrac{22}{7} \times r} \\ \\ \sf{\dashrightarrow \dfrac{22}{2} \times \dfrac{7}{22} = r} \\ \\ \sf{\dashrightarrow r = \dfrac{7}{2}} \\ \\ \sf{\dashrightarrow r = 3.5 \: cm}$

$\rule{150}{2}$

$\bf{Now,} \\ \\ \sf{\dashrightarrow Area \: of \: quadrant = \dfrac{1}{4} \times Area \: of \: circle} \\ \\ \sf{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \dfrac{1}{4} \times \dfrac{22}{7} \times \bigg(\dfrac{7}{2}\bigg)^2} \\ \\ \sf{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \dfrac{1}{4} \times \dfrac{22}{7} \times \dfrac{49}{4}} \\ \\ \sf{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\dfrac{1078}{112}}$

$\\ \\ \sf{\dashrightarrow Area \: of \: quadrant = 9.625 \: cm^2$