Question

Find the area of a quadrant of a circle whose circumference is 22 cm​

Answer 1

Answer:

Circumference of the circle = 22 cm

21tr = 22 cm

r=

22x7

2x22

= - cm

Area of the quadrant= lm2

4

1 22 7 7 77 2 = -X-X-X-=- cm

4 7 2 2 8

Answer 2

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Circumference of the circle, C = 22 cm (given)

It should be noted that a quadrant of a circle is a sector which is making an angle of 90°.

Let the radius of the circle = r

As C = 2πr = 22,

R = 22/2π cm = 7/2 cm

∴ Area of the quadrant = (θ/360°) × πr2

Here, θ = 90°

So, A = (90°/360°) × π r2 cm2

= (49/16) π cm2

= 77/8 cm2 = 9.6 cm2