Question

Find the area of a quadrilateral ABCD having vertices at A(1, 2), B(1, 0), C(4, 0) and D(4, 4).

Answer 1

Answer:

Step-by-step explanation:

The correct answer is 9 sq unit

Answer 2

9 sq. units.

Step-by-step explanation:

If we plot the points on the x-y plane, then we can easily identify the quadrilateral ABCD and it is a trapezoid having parallel sides AB and CD and height is BC.

Now, the length of segment AB = (2 - 0) = 2 units and the length of the segment CD = (4 - 0) = 4 units and height BC = (4 - 1) = 3 units.

Therefore, the area of ABCD = $\frac{1}{2}\times BC \times (AB + CD) = \frac{1}{2}\times 3 \times (2 + 4) = 9$ sq. units. (Answer)