Question

Find the area of a quadrilateral ABCD having vertices at A(1, 2),
B(1,0), C(4,0) and D(4,4).​

Answer 1

Answer:

i think the answer is 9 sq units because when we get area of one triangle its 3 and other is 6 so add and get 9

Step-by-step explanation:

Answer 2

Given:-

A(1,2) , B(1,0) , C(4,0) ,D(4,4) are the vertices of quadrilateral ABCD

To find = THE area of the quadrilateral ABCD.

Solution-

- Let BD be the diagonal of quadilateral ABCD

- Therefore, ar of quad ABCD= ar (triangle ABD)+ ar (triangle BDC)

Area of triangle ABD

= 1/2[x1(y2-y3) -x2(y3-y1) -x3(y1-y2)]

=1/2[1(0-4)+1(4-2)+4(2-0)]

=1/2[-4+2-8]

= 6/2

= 3 sq. units

- Area of triangle BDC

= 1/2[1(4-0)+4(0-0)+4(0-4)]

=1/2[4+0-16]

=1/2×-12

= 6 sq. units

- The area of quadrilateral ABCD

= ar of triangle ABD + ar of triangle BDC

= 3 + 6

= 9 sq. units

-*Hence , The area of quadrilateral ABCD = 9 sq.units*