Question

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm. CD = 4 cm, DA-5cm and AC=Scm.​

Answer 1

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$\huge\red{\tt{\underline{Question:-}}}$

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm. CD = 4 cm, DA-5cm and AC=Scm.

$\huge\red{\tt{\underline{Answer:-}}}$

In a quadrilateral ABCD, AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. ∴ ΔABC is right angled with ∠B = 90°. = 2 x 4.6 cm2 (approx.)

=> 9.2 cm2 (approx.)

Thanks.

Answer 2

Answer:

Hence, the area of the quadrilateral ABCD is = 15•2cm

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