Question

Find the area of a quadrilateral ABCD, in which AB=5 cm, BC=4 cm,CD=4 cm, DA=5 cm and AC=7 cm.

Answer 1

In triangle ΔABC, observe that,

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given by

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given byIn ΔACD all the sides are known, so just use Heron’s formula to find out Area of triangle ΔACD,

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given byIn ΔACD all the sides are known, so just use Heron’s formula to find out Area of triangle ΔACD, s=AD+DC+AC2=5+4+52=7 cm

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given byIn ΔACD all the sides are known, so just use Heron’s formula to find out Area of triangle ΔACD, s=AD+DC+AC2=5+4+52=7 cmThe area of the ΔACD is:

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given byIn ΔACD all the sides are known, so just use Heron’s formula to find out Area of triangle ΔACD, s=AD+DC+AC2=5+4+52=7 cmThe area of the ΔACD is:Area of quadrilateral ABCD will be,

In triangle ΔABC, observe that,So the triangle ΔABC is right angled triangle.Area of right angled triangle ΔABC, is given byIn ΔACD all the sides are known, so just use Heron’s formula to find out Area of triangle ΔACD, s=AD+DC+AC2=5+4+52=7 cmThe area of the ΔACD is:Area of quadrilateral ABCD will be,Area = Area of triangle ABC + Area of triangle ADC

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