Question

Find the area of a quadrilateral ABCD in which AB = 8 cm, BC = 6 cm, CD = 8
cm, DA = 10 cm and AC = 10 cm.

Answer 1

Answer:

Area of quadrilateral ABCD is the sum of areas of triangles ABC & ADC

Use the formula of area of a triangle with sides a, b and c as [math]\Delta =√s(s-a)(s-b)(s-c)[/math] where the perimeter is given by [math]2s=a+b+c[/math]. So area of triangle [math]\Delta ABC=√12(12-8)(12-6)(12-10)=√12*4*6*2=24[/math] square cm & area of [math]\Delta ADC=√14(14-10)(14-10)(14-8)=8√21\sim 8*4.58= 36.66[/math] square cm

So, the area of the quadrilateral is [math]24+36.66=60.66[/math] square cm.