Question

find the area of a quadrilateral ABCD in which AB=8cmv,BC=6cm ,CD=8cm ,DA=10cm and angle B= 90°​

Answer 1

Step-by-step explanation:

Use the formula of area of a triangle with sides a, b and c as Δ=√s(s−a)(s−b)(s−c) where the perimeter is given by 2s=a+b+c . So area of triangle ΔABC=√12(12−8)(12−6)(12−10)=√12∗4∗6∗2=24 square cm & area of ΔADC=√14(14−10)(14−10)(14−8)=8√21∼8∗4.58=36.66 square cm

So, the area of the quadrilateral is 24+36.66=60.66 square cm.