Question

find the area of a quadrilateral ABCD in which angle A =90°,AB=32 cm,AD=24 cm and BC=CD=25cm

Answer 1

mark as the brainlist as fast as possible

Answer 2

$\:\:\:\: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal{\bf{\underline{\underline{\huge\mathcal{Answer}}}}}$

$\large\mathcal\red{solution}$

here the quadrilateral is a trapizium and it's parallel sides are DC and AB.....

here ,height is =AD=24cm

therefore we know that the area of a trapizium is ...

$= \frac{1}{2} \times h \times (a + b) \: \: \\ where \: a \: and \: b \: are \: the \: length \: of \: the \: parallel \: sides \\ therefore \: area \: of \: the \: trapizium........ \\\: = \frac{1}{2} \times 24 \times (25 + 32) \: cm {}^{2} \\ = 12 \times 57 \\ = 684 \: cm {}^{2}$

$\large\mathcal\red{hope\: this \: helps \:you......}$