Question

find the area of a quadrilateral ABCD in which BCD is an equilateral triangle each of whom sidea is 26 cm AD is 24cm and BAD is 90 degree also find the perimetar of the quadrilateral

Answer 1

area quadrilateral ABCD=?
area of BCD = 1/4 × √3 × side²
=292.71cm²
area of BAD = 1/2 (base×perpendicular)
=1/2× 26cm × 24cm
=312cm² 

area of quadrilateral ABCD=292.71cm²+312cm² 
=604.7 cm²

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