Question

Find the area of a quadrilateral ABCD in with AB=3cm,BC=4cm,CD=4cm,DA=5cm and AC=5cm

Answer 1

one will be a right angled triangle w ith sides as pythagorean triplet
3 cm , 4cm , 5cm
1
$1 \div 2 \times 4 \times 3$
And other is an isosceles triangle
so area of isosceles triangle
2 root 21
answer is
(6+ 2 root 21)sq.units