find the area of a quadrilateral ABCD which has a diagonal 10 cm and perpendicular on it from opposite vertices that are 6 m and 5 M
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Area of quadrilateral ABCD = 55cm^2
Step-by-step explanation :
Given:
Given:AC= 10 cm
DO = 5 cm
BO = 6 cm
area of TriangleADC;
cmarea of TriangleADC;1/2 x base x height=1/2 x 10 x 6 = 30cm^2
Area of TriangleABC= 1/2 x base height 1/2 x 10 x 5 = 25cm^2
Quadrilateral ABCD = triangle ABC + triangle ADC
AREA OF QUADRILATERAL ABCD = 30+25 cm^2
= 55cm^2
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