Question

Find the area of a quadrilateral ABCD whose diagonal AC is 25cm long and the lengths of perpendiculars from opposite vertices B and D on AC are BE = 3cm and DF =5cm.

Answer 1

area of quadri.ABCD=area of trangle ADC+area of trangle ABC
=(1/2×AC×6)+(1/2×AC×5)
=(1/2×10×6)+(1/2×10×5)
=60/2+50/2
=110/2
=55cm^2

u can do by this method