Find the area of a quadrilateral ABCD whose diagonal AC is 25cm long and the lengths of perpendiculars from opposite vertices B and D on AC are BE = 3cm and DF =5cm.
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ar(ABC)=1/2×25×3=37.5cm^2
ar(ADC)=1/2×25×5=62.5cm^2
ar(ABCD)=37.5+62.5=100cm^2
HOPE THIS WILL HELP U
ar(ADC)=1/2×25×5=62.5cm^2
ar(ABCD)=37.5+62.5=100cm^2
HOPE THIS WILL HELP U
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Hope this answer helps you.
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