Find the area of a quadrilateral ABCDE in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
1.6 cm2 -2√21 cm2
2.- 6 cm2 +2√21 cm2
3.6 cm2 +2√21 cm2
4.6 cm2 +3√21 cm2
Answers
Step-by-step explanation:
Length of rectangle is 30 m.
Breadth of rectangle is 20 m.
Step-by-step explanation:
Given:-
Perimeter of rectangle is 100 m.
To find:-
Length of rectangle.
Breadth of rectangle.
Solution:-
Let, Breadth of rectangle be x m.
And, Length of rectangle be x + 10 m.[We take length be x + 10 m because it is given that length is 10 m more than Breadth.]
We know,
Perimeter of rectangle = 2(Length + Breadth)
Put the values:
\longrightarrow⟶ 100 = 2×(x + 10 + x)
\longrightarrow⟶ 100 = 2x + 20 + 2x
\longrightarrow⟶ 100 = 4x + 20
\longrightarrow⟶ 100 - 20 = 4x
\longrightarrow⟶ 80 = 4x
\longrightarrow⟶ x = 80/4
\longrightarrow⟶ x = 20
Verification:-
\longrightarrow⟶ 100 = 2×(x + 10 + x)
Put x = 20
\longrightarrow⟶ 100 = 2×(20 + 10 + 20)
\longrightarrow⟶ 100 = 2×(30 + 10)
\longrightarrow⟶ 100 = 60 + 10
\longrightarrow⟶ 100 = 100
\boxed{\sf Hence \: Verified.}
HenceVerified.
We have taken,
Breadth be x. So, Breadth of rectangle is 20 m.
Length be x + 10 = 20 + 10 = 30. Thus, Length of rectangle is 30