Question

Find the area of a quadrilateral ABCDE in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.


1.6 cm2 -2√21 cm2
2.- 6 cm2 +2√21 cm2
3.6 cm2 +2√21 cm2
4.6 cm2 +3√21 cm2

Answer 1

Step-by-step explanation:

Length of rectangle is 30 m.

Breadth of rectangle is 20 m.

Step-by-step explanation:

Given:-

Perimeter of rectangle is 100 m.

To find:-

Length of rectangle.

Breadth of rectangle.

Solution:-

Let, Breadth of rectangle be x m.

And, Length of rectangle be x + 10 m.[We take length be x + 10 m because it is given that length is 10 m more than Breadth.]

We know,

Perimeter of rectangle = 2(Length + Breadth)

Put the values:

\longrightarrow⟶ 100 = 2×(x + 10 + x)

\longrightarrow⟶ 100 = 2x + 20 + 2x

\longrightarrow⟶ 100 = 4x + 20

\longrightarrow⟶ 100 - 20 = 4x

\longrightarrow⟶ 80 = 4x

\longrightarrow⟶ x = 80/4

\longrightarrow⟶ x = 20

Verification:-

\longrightarrow⟶ 100 = 2×(x + 10 + x)

Put x = 20

\longrightarrow⟶ 100 = 2×(20 + 10 + 20)

\longrightarrow⟶ 100 = 2×(30 + 10)

\longrightarrow⟶ 100 = 60 + 10

\longrightarrow⟶ 100 = 100

\boxed{\sf Hence \: Verified.}

HenceVerified.

We have taken,

Breadth be x. So, Breadth of rectangle is 20 m.

Length be x + 10 = 20 + 10 = 30. Thus, Length of rectangle is 30