Question

find the area of a quadrilateral if the length of one of its diagonal is 56 cm and the perpendicular distance from the other two vertices to this diagonal are 30 cm and 42 cm ​

Answer 1

SOLUTION

the area is

$= \frac{1}{2} \times base \times height 1+ \frac{1}{2} \times base \times height 2\\ = \frac{1}{2} \times base \times (height1 + height2)$

here height 1=the perpendicular distance=30 cm

and height 2=42 cm

base =diagonal=56 cm

$\frac{1}{2} \times 56 \times (30 + 42) \\ = 28 \times 72 \: cm {}^{2} \\ = 2016 \: \: cm {}^{2}$

Answer 2

Step-by-step explanation:

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