Question

Find the area of a quadrilateral in which the length of one of the diagonals in 20m
and perpendiculars (I.e. offsets) drawn to it from the opposite vertices are 11m
and 9 m​

Answer 1

Answer:

Area of 2 triangles gives the area

of the quadrilateral

1) Area of triangle = 1/2bh

= 1/2bh=1/2 x 20 x 11 = 110m2

2) Area of 2nd triangle = 1/2bh

= 1/2 x 20 x 9 = 90m2

Total area=110+90 = 200 m2. Ans

Answer 2

Answer:

200 m^2

Step-by-step explanation:

area of quadrilateral=1/2*diagonal*sum of offsets

area=1/2*20m*(11+9)m

=1*10m*20m

=200m^2

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