find the area of a quadrilateral one of whose diagonals is 40 cm and the length of the perpendicular drawn from the opposite vertices on the diagonal are 16 cm and 12 CM
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Answer:
Area of General quadrilateral =1/2×DIAGONAL(height1 + height2)
Step by step :
1} Diagonal=40cm
Height1=16cm
Height2=12cm
2}Area=1/2×40( 16 + 14 )
3} Solve the obtained
equation=1/2×40×30
=1/2×1200
=1200/2
=600 cm
4}Area of quadrilateral=600cm
=6m
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