Question

find the area of a quadrilateral pqrs in which pq=6 qr =8 Rs= 8 and ps= 10 <pqr=90°​

Answer 1

Answer:

Step-by-step explanation:

<PQR is a right angled triangle.

PQ is the base and QR is the height.

Area of Δ PQR = 1/2 x PQ x QR

= 1/2 x 6 x 8

= 24 cm2.

Also, PR2 = PQ2 + QR2

PR2 = 36+ 64

PR2 = 100

PR = 10

<PQR is a right angled triangle.

⇒ PR2 = PS2 + SR2

⇒ 100= PS2 + 64

⇒ PS2 = 36

⇒ PS = 6

SR is the base and PS is the height.

Area of Δ PSR = 1/2 x SR x PS

= 1/2 x 8 x 10

= 40 cm2.

Total area of the quadrilateral = 40+6 = 46 cm2