Find the area of a quadrilateral PQRS whos diagonal SQ = 12cm , and lengths of perpendicular from opposite vertices P and R are PL = 2.6 cm and RM = 8.4 cm .
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Given,
SQ= 12 cm
PL= 2.6 cm
RM= 8.4 cm
Area of a quadrilateral PQRS = Area of ∆PSQ+Area of ∆RQS.
= ½×SQ×RM+½×SQ×PL
= ½×SQ(RM+PL)
= ½×12(8.4+2.6)
= ½×12(11)
= ½×12×11
= 6×11
= 66 cm²
.
. . Area of a quadrilateral PQRS is 66 cm².
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