find the area of a quadrilateral whose diagonal is of length 70 m and lengths of the perpendicular drawns from the opposite vertices on the diagonal are of length 42 m and 50 m respectively
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the ans is 1887m^2.....
=(1/2*70*42)+(1/2*70*50)m^2
=(147+1750)m^2
=1887m^2
Actually the diagonal is dividing the quadrilateral into two triangles ..so the perpendiculars becomes the two heights of two triangles and the diagonal of the quadrilateral besomes it's base ...so we can find the area of two triangles by the formula (1/2 * base * height) where
1st triangle = base = 70m and height=42 m
and 2nd triangle =base =70m and height=50m
now add those two area and you will get the are aof the quardrailateral
=(1/2*70*42)+(1/2*70*50)m^2
=(147+1750)m^2
=1887m^2
Actually the diagonal is dividing the quadrilateral into two triangles ..so the perpendiculars becomes the two heights of two triangles and the diagonal of the quadrilateral besomes it's base ...so we can find the area of two triangles by the formula (1/2 * base * height) where
1st triangle = base = 70m and height=42 m
and 2nd triangle =base =70m and height=50m
now add those two area and you will get the are aof the quardrailateral
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