Math, asked by 2602alpha, 7 months ago

Find the area of a quadrilateral whose one of the diagonals is 12cm and the length of the perpendiculars drawn from its opposite vertices are 3.5 cm and 4 cm respectively.

Answers

Answered by nisha02345
10

Answer:

Area=21

×One diagonal×Sum of the length of the perpendiculars drawn from it on the remaining two vertices.

=21

×70×(42+50)

=35×92=3220‬sq.m

Answered by Anonymous
11

Answer:

Area=21

×One diagonal×Sum of the length of the perpendiculars drawn from it on the remaining two vertices.

=21

×70×(42+50)

=35×92=3220‬sq.m

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