Find the area of a quadrilateral whose one of the diagonals is 12cm and the length of the perpendiculars drawn from its opposite vertices are 3.5 cm and 4 cm respectively.
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Answered by
10
Answer:
Area=21
×One diagonal×Sum of the length of the perpendiculars drawn from it on the remaining two vertices.
=21
×70×(42+50)
=35×92=3220sq.m
Answered by
11
Answer:
Area=21
×One diagonal×Sum of the length of the perpendiculars drawn from it on the remaining two vertices.
=21
×70×(42+50)
=35×92=3220sq.m
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