Question

Find the area of a quadrilateral with diagonal 13m and offset 7m and 3m

Answer 1

Question:Find the area of a quadrilateral with diagonal 13m and offset 7m and 3m.

Answer:

$65 \: {m}^{2}$

Given:

A quadrilateral ABCD having diagonal13 m and it's offset 7m and 3m

To find:

Area of the quadrilateral

Solution:-

• Diagonal=13 m;offset=7m and 3m

We know that

$area \: of \: quadrilateral = \frac{1}{2} \times (diagonal) \times (sum \: of \: it's offsets)$

$= \frac{1}{2} \times 13(3 + 7)$

$= \frac{1}{2} \times 13 \times 10$

$= 13 \times 5$

$= 65 \: {m}^{2}$

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Area of quadrilateral is 65 m^2

Answer 2

Answer:

$formula \:$

$area \: of \: quadrilateral \: = \frac{1}{2} \times (diagonal)$

$= \frac{1}{2} \times 13( \: 3 \: + 7)$

$\frac{1}{2} \times 13 \times 10$

$13 \: \times 5$

$= {65m}^{2}$

$area \: of \: quadrilateral \: = {65m}^{2}$