Find the area of a.qualdrilateral ABCD in which AD= 24cm, angle BAD = 90° and BCD forms an equilateral triangle whose each sides is equal to 26 cm.
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We need to find area of ABCD
In triangle BAD, we have
BD2 = BA2 + AD2 .So

Area of right angled triangle ABD, say A1is given by

Where,
Base = BA = 10 cm; Height = AD = 24 cm

Area of equilateral triangle BCD, say A2having sides a, b, c is given by
, where
a = BC = CD = BD = 26 cm

Area of quadrilateral ABCD, say A
A = Area of triangle BAD + Area of triangle BCD

In triangle BAD, we have
BD2 = BA2 + AD2 .So

Area of right angled triangle ABD, say A1is given by

Where,
Base = BA = 10 cm; Height = AD = 24 cm

Area of equilateral triangle BCD, say A2having sides a, b, c is given by
, where
a = BC = CD = BD = 26 cm

Area of quadrilateral ABCD, say A
A = Area of triangle BAD + Area of triangle BCD

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