Question

find the area of a quardilateral ABCD points are A(-2,8) B(-3,2) C(3,1) D(4,7)​

Answer 1

Answer:

ANSWER

Let, the points be A(−2,−2),B(5,1),C(2,4) and D(−1,5)

The quadrilateral ABCD can be divided into triangles ABC and ACD and hence the area of the quadrilateral is the sum of the areas of the two triangles. 

Area of a triangle with vertices (x1,y1) ; (x2,y2) and (x3,y3)

=∣∣∣∣∣∣2x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣∣∣∣∣∣.

Hence, substituting the points (x1,y1)=(−2,−2) ; (x2,y2)=(5,1)  and (x3,y3)=(2,4) in the area formula, 

we get area of triangle ABC  

=∣∣∣∣∣∣2

Step-by-step explanation:

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Answer 2

Answer:

the answer is 15

Step-by-step explanation:

1/2×30=15