Question

find the area of a quardilateral one of whose diagonals is 40cm and the length of the perpendicular draw from the opposite vertices on the diagonal are 16 cm and 12cm​

Answer 1

${ \huge{ \boxed{ \underline{ \overline{ \overline{ \overline{ \underline{ \mathtt\purple{AnSweR☃}}}}}}}}}$

Area of quadrilateral= 1/2 × diagonal( Some of perpendiculars )

Area = 1/2 × 40cm × (16+12) cm

Area = 1/2 × 40cm × 28 cm

Area = 20 cm× 28 cm

= 560cm^2

$\huge \tt \colorbox{plum}{@janvi}$

Answer 2

$\huge\star\underline\mathfrak\red{Answer:-}$

Area of quadrilateral= 1/2 × diagonal( Some of perpendiculars )

Area = 1/2 × 40cm × (16+12) cm

Area = 1/2 × 40cm × 28 cm

Area = 20 cm× 28 cm

= 560cm²

HOPE SO IT WILL HELP......

PLEASE MARK IT AS BRAINLIST.....