Question

find the area of a quardrilateral ABCD in which AB =9 cm, BC = 40 cm ,Angle ABC = 90 degree , CD = 15 cm , AD = 28 cm
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Base = 40 height 9. ...

Area of triangle abc = 180....

And the diagonal of quadrilateral is 41....

1600 +81 = 41^2

Then the sides of other triangle are 41 ,28,15

The area of triangle root s* s-a* s-b*s-c

Is 126

The area of quadrilateral is 180+126=306