Question

find the area of a quarilateral one of whose diagonals is 40 cm. and the lengths of the perpendiculars drawn from the opposite vertices in the diagonal are 16 cm and 12 cm​

Answer 1

Answer:

Area= 1/2×one diagonal×Sum of the

lengths of the perpendiculars drawn

from it on the remaining two vertices.

1/2×40(16+14)

20×30

=600sq.cm

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