Question

find the area of a rbombus whose side is 5cm and whose altitude is 4.8 cm.if one of its diagonals is 8cm long, find the length of the other diagonal ?

Answer 1

Answer:

Length of the other diagonal is 6 cm.

Answer 2

Answer:

Given:

side = 5 cm

height= 4.8 cm

diagonal 1 = 8 cm

diagonal 2 = ?

Solution:

Area of rhombus = $\frac{1}{2}$ × $d_{1}$ × $d_{2}$

Area of parallelogram = base × height

=5 × 4.8

= 24 $cm^{2}$

Area of rhombus = $\frac{1}{2}$ × $d_{1}$ × $d_{2}$

⇒ 24 $cm^{2}$ = $\frac{1}{2}$ × 8 × $d_{2}$

⇒ $\frac{24 * 2}{8}$ = $d_{2}$

⇒$\frac{48}{8}$ = $d_{2}$

⇒ $d_{2} = 6$ cm.

Length of the other diangonal is 6 cm.

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