Question

find the area of a reactangle whose breadth is half the length and breadth is 19 cm
.The topic is perimeter and area

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Answer 1

Answer:

722cm²

Step-by-step explanation:

Area of a Rectangle = l × b

=> (38 × 19) cm²

=> 722cm²

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Answer 2

Given:-

• Length of a rectangle is 19 cm.
• Breadth of the rectangle is half of its length.

To find:-

• The area of the rectangle.

Formula used:-

• Area of rectangle = (lb) sq.units

Solution:-

According to the question, let's take the value of breadth as $\sf{\frac{Length}{2}}$.

As we are asked to find the area of the rectangle, we shall find it by substituting the measures in the formula:

$\leadsto{\textbf{\textsf{\purple{lb\:sq.units}}}}$

$\\ \:\:\:\:\:\:\:\Rightarrow{\bf{Length\times \dfrac{Length}{2}}}$

$\\ \:\:\:\:\:\:\:\Rightarrow{\bf{19\times \dfrac{19}{2}}}$

$\\ \:\:\:\:\:\:\:\Rightarrow{\bf{\dfrac{19\times 19}{2}}}$

$\\ \:\:\:\:\:\:\:\Rightarrow{\bf{\dfrac{361}{2}}}$

$\\ \:\:\:\:\:\:\:\Rightarrow{\boxed{\boxed{\frak{\red{108.5\:cm^2}}}}}$

$\\ \therefore\underline{\sf{The\:area\:of\: the\: rectangle\:is\:\textsf{\textbf{\pink{108.5\:m ^2 }}}\sf{.}}}$

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Some formulae for AREA:-

$\begin{gathered}\\\:\:\:\sf{\bullet\: Trapezium=\dfrac{1}{2}h(sum\: of\: parallel\:sides)\:sq.units}\end{gathered}$

$\begin{gathered}\\\:\:\:\sf{\bullet\: Parallelogram=bh\:sq.units}\end{gathered}$

$\begin{gathered}\\\:\:\:\sf{\bullet\: Rhombus=\dfrac{1}{2}d_1d_2\:sq.units}\end{gathered}$

$\begin{gathered}\\\:\:\:\sf{\bullet\: Rectangle=lb\:sq.units}\end{gathered}$

$\begin{gathered}\\\:\:\:\sf{\bullet\: Circle=\pi r^2\:sq.units}\end{gathered}$

$\begin{gathered}\\\:\:\:\sf{\bullet\: Semi\: circle=\dfrac{1}{2}\pi r^2\:sq.units}\end{gathered}$