Find the area of a reactangular plot whose one side is 8 m long and diagnol is of length 10 m
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Answered by
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By Pythagoras theorem
Diagonal²=side²+II side²
10²-8²=II side²
100-64=II side²
36=II side²
6=II side
Area =hieght* base
Area =6*8
Area =48m²
Diagonal²=side²+II side²
10²-8²=II side²
100-64=II side²
36=II side²
6=II side
Area =hieght* base
Area =6*8
Area =48m²
Answered by
1
I hope it will help you
Rectangle properties are,
Each angle is 90°
Therefore,
By Pythagoras thereon
h^2 = a^2 + b^2
10^2 = 8^2 + b^2
100-64 = b^2
36 = b^2
6m = b
Therefore,
Area of rectangle = l× b
6×8
48m^2
Rectangle properties are,
Each angle is 90°
Therefore,
By Pythagoras thereon
h^2 = a^2 + b^2
10^2 = 8^2 + b^2
100-64 = b^2
36 = b^2
6m = b
Therefore,
Area of rectangle = l× b
6×8
48m^2
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