Question

find the area of a rectangle and a square are equal .if the length of the rectangle is 16cm and its brath is 9cm ,find the length of the side of teh square​

Answer 1

AREA

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Solve:

$\begin{align}& \sf Area \: of \: rectangle=lw \\ & \sf Area \: of \: square = {s}^{2} \end{align}</p><p>$

$\large \tt \red{given} \begin{cases} \sf \: lw= {s}^{2} \\ \sf \: l = 16cm \\ \sf \: w = 9cm \end{cases}$

$\large \implies \sf \Large 16cm \cdot9cm = {s}^{2}$

$\large \implies \sf \Large 144 {cm}^{2} = {s}^{2}$

$\large \implies \sf \Large \sqrt{144 {cm}^{ \cancel2} } = \sqrt{ {s}^{ \cancel2} }$

$\large \implies \sf \Large \therefore \: 12cm = {s}$

$\:$

Final Answer:

$\Large \sf \orange{The \: sides \: are \: 12cm \: long}$

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Answer 2

Answer:

12

Step-by-step explanation:

According to question

l*b=a*a

16*9=a*a

a=$\sqrt{144}$

a=12