Question

Find the area of a rectangle having lenght 12 cm and width 9 cm​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

Given:

Length of Rectangle =12 cm

Breadth (width) of Rectangle=9cm

To Find:

Area of rectangle

$\bold{\underline{\underline{Rectangle}}}$

• A rectangle is a Quadrilateral having four sides and four vertex.
• Interior angle is equal to $360^{\circ}$and each angle makes a $90^{\circ}$angle.
• Opposite sides of rectangle are equal and parallel.
• Diagonals bisect each other.
• Area is equal to the product of its length and breadth.

Area of Rectangle= $\sf Length \times breadth$

$\sf= > 12 \times 9 = 108 {cm}^{2}$

$\therefore$ Area of Rectangle is $\sf {\red{108 {cm}^{2}}}$

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

Given:

Length of Rectangle =12 cm

Breadth (width) of Rectangle=9cm

To Find:

Area of rectangle

$\bold{\underline{\underline{Rectangle}}}$

A rectangle is a Quadrilateral having four sides and four vertex.

Interior angle is equal to $360^{\circ}$and each angle makes a $90^{\circ}$angle.

Opposite sides of rectangle are equal and parallel.

Diagonals bisect each other.

Area is equal to the product of its length and breadth.

Area of Rectangle= $\sf Length \times breadth$

$\sf= > 12 \times 9 = 108 {cm}^{2}$

$\therefore$ Area of Rectangle is $\sf {\red{108 {cm}^{2}}}$