find the area of a rectangle if the perimeter is 300 CM and the length and breadth are in the ratio of 1:2
Answers
Answered by
15
let length = x
breadth = 2x
perimeter of rectangle = 2(l+b)
300= 2(x+2x)
150=3x
x=50
length = 50
breadth = 100
area of rectangle = l×b
50×100=5000 square cm
breadth = 2x
perimeter of rectangle = 2(l+b)
300= 2(x+2x)
150=3x
x=50
length = 50
breadth = 100
area of rectangle = l×b
50×100=5000 square cm
Answered by
12
Heya,
PERIMETER= 300cm
Ratio= 1:2
Let's assume that the ratio are 1x and 2x
So,
Length=1x
Breadth=2x
Perimeter formula:-
Perimeter=2 (l+b)
=> 300=2 (1x+2x)
=> 300=2 (3x)
=> 300=6x
=> 300/6=x
=> 50=x
Therefore,
Length=1x=1×50=50cm
Breadth=2x=2×50=100cm
To find area:-
Area= l×b
=> Area= 50×100
=> Area= 5000sq.cm
Hence the area of the rectangle is 5000sq.cm
Hope my answer helps you :)
Regards,
Shobana
PERIMETER= 300cm
Ratio= 1:2
Let's assume that the ratio are 1x and 2x
So,
Length=1x
Breadth=2x
Perimeter formula:-
Perimeter=2 (l+b)
=> 300=2 (1x+2x)
=> 300=2 (3x)
=> 300=6x
=> 300/6=x
=> 50=x
Therefore,
Length=1x=1×50=50cm
Breadth=2x=2×50=100cm
To find area:-
Area= l×b
=> Area= 50×100
=> Area= 5000sq.cm
Hence the area of the rectangle is 5000sq.cm
Hope my answer helps you :)
Regards,
Shobana
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