find the area of a rectangle in which both tue sides r a cemi corcle of 56m and the langht of the triangle is 90m
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Answer:
7491.4 m^2
Step-by-step explanation:
radius = diameter/2 = 56/2= 28m
Area = (Area of rectangle )+ (Area of two
semicircle)
Area = ( lenght × breath ) + { (πr^2)/2 + (πr^2)/2 }
Area = (90 × 56) + { (π/2)(28×28+28×28) }
Area = 5040 + { (22/7)(780) }
Area = (5040 + 2451.4 )m^2
Area = 7491.4 m^2
Answered by
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Area of semicircle = 1/2 πr² = 1/2 ×22/7 × 56/2 = 44cm²
Area of rectangle = l× b = 56 ×90 = 5040 cm²
Area of figure = 2× 44 + 5040 = 5128 cm²
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