Math, asked by sudaykshetty, 6 months ago

find the area of a rectangle in which both tue sides r a cemi corcle of 56m and the langht of the triangle is 90m​

Attachments:

Answers

Answered by pushpendergill
1

Answer:

7491.4 m^2

Step-by-step explanation:

radius = diameter/2 = 56/2= 28m

Area = (Area of rectangle )+ (Area of two

semicircle)

Area = ( lenght × breath ) + { (πr^2)/2 + (πr^2)/2 }

Area = (90 × 56) + { (π/2)(28×28+28×28) }

Area = 5040 + { (22/7)(780) }

Area = (5040 + 2451.4 )m^2

Area = 7491.4 m^2

Answered by anurag2147
0

Area of semicircle = 1/2 πr² = 1/2 ×22/7 × 56/2 = 44cm²

Area of rectangle = l× b = 56 ×90 = 5040 cm²

Area of figure = 2× 44 + 5040 = 5128 cm²

Similar questions