Question

Find the area of a rectangle of length ab^2c and breadth bc^2​

Answer 1

GIVEN :

Length of a rectangle = ab²c

Breadth of a rectangle = bc²

Now, Area of the rectangle :

=2(l+b)

=2(ab²c + bc²) [(a+b)(a+b)=a²+2ab+b²]

=2[abc² + (2×abc×bc) + bc²]

=2(a²b²c² + 2ab²c² + b²c²)

=2a²b²c² + 4ab²c² + 2b²c²

=6ab²c² + 2b²c²

$\fbox{ 6ab²c² + 2b²c² }$ is the answer

Hence, area of the rectangle is 6ab²c² + 2b²c²

$\mathfrak{ Thnk \: my \: this \: answer }$

Answer 2

Answer:

ab^3c^

Step-by-step explanation:

Length = ab^2c

Breadth = bc^2

Area of a rectangle = l*b

ab^2c*bc^2

Multiply them

Multiplying b^2 with b you get b^3

Multiplying c with c^2 you get c^3

a will remain the same

Therefore you get the answer ab^3c^3

Hope this helped ^^