Question

find the area of a rectangle whose breadth is 5 and length is thrice of square of breadth.​

Answer 1

Answer:

Given

Breadth = (2a + b)

Length 3 times breadth

To Find

Area

Solution

First, we need to find the length

Length 3(2a + b)

Length= 6a + 3b

Now

Area = Ib

Area (6a +3b)(2a +b)

Area (6a x 2a) + (6a x b) + (3b x 2a) + (3b

x b)

Area 12a2 + 6ab + 6ab +3b2

Area 12a +12ab + 3b

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Answer 2

Given :

• Breadth is 5 .
• Length is thrice the square of Breadth .

To Find :

• Area of the Rectangle = ?

Solution :

We know That :

• ✯ Area of Rectangle = Length × Breadth ✯

According to the Question :

• Length = 5
• Breadth = 5² × 3

Calculating the Area :

➙ Area = Length × Breadth

➙ $\qquad$ 5 × 5² × 3

➙ $\qquad$ 5 × 25 × 3

➙ $\qquad$ 5 × 75

➙ $\qquad \; \; {\red{\sf{375 \: units²}}}$

Therefore :

Area of the Rectangle is 375 units² .

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