Question

Find the area of a rectangle whose breadth is 7 m and its perimeter is equal to that of a square with side 12 m.​

Answer 1

Answer:

perimeter of square=4×s

=4×12=48m

perimeter of square =perimeter of rectangle

48=2(l+b)

48=2(l+7)

48=2l+14

34=2l

17 m =length

area = l ×b

=17×7=119 square meters

Answer 2

Given:

breath - 7m

perimeter = perimeter of the square which has the sides of 12 each.

To Find:

area of the rectangle

Solution:

Since the perimeter is similar to that of the perimeter of the square

Finding the perimeter of the square:

$The \: perimeter \: of \: the \: square = 4 \times sides$

$The \: perimeter \: of \: the \: square = 4 \times 12$

$The \: perimeter \: of \: the \: square = 48$

since the perimeter for both the square and the rectangle is equal-

Therefore, the perimeter of the rectangle= 48m/s

let the length of the rectangle be l

$The \: perimeter \: of \: the \: square = The \: perimeter \: of \: the \: rectangle$

adding the given values

$48 = 2(l \times w)$

$48 = 2(l \times 7)$

$48 = 14l$

$l \: = \frac{48}{14}$

$l = 3.428$

Area of the rectangle,

$Area = l \times w$

$Area = 14 \times 3.428$

$Area = 47.99$

Therefore, the area of the rectangle is 47.99 m²