find the area of a rectangle whose length and breadth are 3x + 2y and 4x-3y respectively. (please say the answer )
Answers
Step-by-step explanation:
length = 3x + 2y
breadth = 4x - 3y
area = lb
= 3x + 2y (4x - 3y)
= 3x(4x - 3y) + 2y(4x - 3y)
= 12x^2 - 9xy + 8yx - 6y^2
= 12x^2 - xy - 6y^2
Hope it's helpful.........
The answer is 12x^2 - xy - 6y^2
Area of a rectangle:
Any shape's area can be calculated by counting how many unit squares will fit inside of it. A square with a side of 1 unit is referred to as a unit square in this context. Therefore, the quantity of unit squares that make up a rectangle's perimeter is its area. The area of a rectangle is an alternative term for the area contained within a rectangle's border.
The flat surfaces of laptop monitors, blackboards, painting canvases, etc. are a few instances of rectangular shapes.
Solution:
Let length of the rectangle = 3x + 2y
Let breadth of the rectangle = 4x - 3y
Area = length x breadth
= 3x + 2y (4x - 3y)
= 3x(4x - 3y) + 2y(4x - 3y)
= 12x^2 - 9xy + 8yx - 6y^2
= 12x^2 - xy - 6y^2
Therefore, the area of the rectangle is 12x^2 - xy - 6y^2
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