Question

Find the area of a rectangle whose length and breadth (x+y)and(x^2-xy+y^2) respectively

Answer 1

Answer:

$x^{3} +y^{3}$

Step-by-step explanation:

Perimeter of a rectangle = lb

l = (x+y)

b= $(x^{2} -xy +y^{2} )$

(x+y)  $(x^{2} -xy +y^{2} )$

$x^{3} -x^{2} y +xy^{2} +yx^{2} -xy^{2} +y^{3}$

= $x^{3} +y^{3}$

therefore the perimeter of the rectangle is ($x^{3} +y^{3}$)...

hope this helps

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