Question

find the area of a rectangle whose length is 116 m and breadth is one- fourth of the length
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Answer 1

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$\rm \huge \purple{ Solution :}$

$\rm Let \: the \: breadth \: be \: \purple{ B\: m }\\ \rm and \: the \: length \: be \: \purple{L \: m.}$

$\rm Given \: , \: B = \frac{1}{4} (L)\\ </p><p>\rm B=L/4 \\ </p><p>\rm B=116/4 \\ </p><p>\rm B= \purple{29}$

$\rm Therefore, \\ \rm Area \: of \: rectangle=L*B \\ </p><p>\rm =L*B \\ </p><p>\rm =116*29 \\ </p><p> \rm = \purple{3364m^2.}$

$\rm Therefore, \: area \: = \: \purple{3364m^2.}$

$\rm \large \purple { Hence \: Verified :) }$

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