Question

Find the area of a rectangle whose length is 2.6cm and breadth is 1.5cm?​

Answer 1

Area of rectangle = L × B

2.6 × 1.5

= 3.9

More information :-

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

Answer:

3.9cm^2

Step-by-step explanation:

area of a rectangle=lxb

given

length of the rectangle=2.6 cm

breadth of the rectangle= 1.5 cm

thus area= 2.6x1.5

=3.9 cm^2

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