Question

find the area of a rectangle whose length is (2x+3)units and breadth is (2x+5) units​

Answer 1

$\Huge{\texttt{{{\color{Magenta}{⛄A}}{\red{N}}{\purple{S}}{\pink{W}}{\blue{E}}{\green{R}}{\red{♡}}{\purple{࿐⛄}}{\color{pink}{:}}}}}$

$\sf \red{area \: of \: rectangle= length × breadth}$

$\sf \pink{ \longrightarrow(2x+3)×(2x+5)}$

$\sf \pink{ \longrightarrow4x^{2} +10x+6x+15}$

$\sf \pink{(4x^{2} +16x+15)}$

$\boxed{ \tt{(4x^2+16x+15) } \: units \: square}$

$\huge\red{\boxed{\orange{\mathcal{{{\fcolorbox{red}{i}{{\red{@Master}}}}}}}}}$

Answer 2

length - 2x + 3

breadth - 2x + 5

area of rectangle = l x b

= (2x + 3)(2x + 5)

= 4x² + 10x + 6x + 15

= 4x² + 16x + 15

therefore, the area of rectangle is 4x² + 16x + 15.