Question

FIND THE AREA OF A RECTANGLE WHOSE LENGTH IS THRICE ITS BREADTH WHERE, BREADTH IS 4x

Answer 1

Step-by-step explanation:

ANSWER:-

Question :-

Find the area of a Triangle whole length is thrice the breadth and breadth is 4x.

Given that:-

• Length = 3× 4x
• Breadth = 4x
• Area = ?

Concept:-

Area = Length × Breadth

Let's Do!

$\rm{Area = 12x \times 4x}$

We know that:-

$\rm{x \times x = x^2}$

And also,

$\rm{12 \times 4 = 48}$

So,

$\rm{Area = 48 \ x^2}$

So, this is the required Answer.

What if we need to find Perimeter?

We need to know that:-

Perimeter = 2 ×( L+ B)

$\rm{Perimeter = 2( \ 12x+x)}$

$\rm{Perimeter = 2(13x)}$

$\rm{Perimeter = 36x}$ would be the answer.

Answer 2

$\bf \red{ \underline{Question : }}$

Find the area of a rectangle whose length is thrice its breadth where, Breadth is 4x.

$\bf \red{ \underline{Answer:}}$

• Breadth of a rectangle= 4x
• Length is thrice it's Breadth = 3(4x) = 12x

$\boxed {\mathfrak{Area \: \: of \: \: Rectangle= l × b}}$

→Area of Rectangle = 4x * 12x

→Area of Rectangle = 48x²

$\boxed {\purple{\mathfrak{\therefore \: Area \: \: of \: \: Rectangle \: \: = 48 \: x²}}}$