Question

find the area of a rectangle whose length is thrice its breadth where breadth is 4x​

Answer 1

Given Information :

• Length = Thrice its breadth

• Breadth = 4x

Solution:

Here, we have to find the area of the rectangle. So,

$\sf{ \longrightarrow \: Breadth = 4x } \\ \\ \sf{ \longrightarrow \: Length = Thrice \: its \: breadth} \\ \\ \sf{ \longrightarrow \: Length = 3(4x)} \\ \\ \sf{ \longrightarrow \: Length = 12x}$

We got the value of length that is 12x. Now, we have to calculate the area of the rectangle, so by substituting the values in the formula of the area of the rectangle, we can find its area.

$\sf{ \longrightarrow \: {Area}_{(Rectangle)} = Length \times Breadth} \\ \\ \sf{ \longrightarrow \: {Area}_{(Rectangle)} = (12x) \times (4x)} \\ \\ \sf{ \longrightarrow \: {Area}_{(Rectangle)} = (12 \times 4) \times (x \times x)} \\ \\ \sf{ \longrightarrow \: {Area}_{(Rectangle)} = (48) \times ( {x}^{2} )} \\ \\\longrightarrow \underline{ \boxed { \sf{{Area}_{(Rectangle)} = 48{x}^{2}} }} \red{ \bigstar}$

$\therefore \underline{ \sf{Area \: is \textbf{ \textsf{ 48x}}} {}^{2} \: units.}$

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$\: \: \: \ \: \: \: \: \: \: \: \: \: \: \: \underline{ \sf{ \star \: More \: information \: \star}}$

• Opposite sides of a rectangle are equal.

• Opposite sides are parallel to each other.

• Diagonals bisect each other.

• Perimeter of rectangular = 2 ( l + b )

• It has 4 right angles.

Answer 2

Breadth = 4x

Length = 3b = 3(4x) = 12x

We know, area of a rectangle = l × b

∴ Area = (4x)(12x)

⇒ Area = 48 sq. units

More:

• Perimeter of rectangle = 2(l + b)
• Diagonal = (l² + b²)^½

(See the above properties given by HealingPearl. They are often handy. Keep in mind that they are bisectors but not perpendicular to each other. This is only limited in kites, squares and rhombi.)