Question

Find the area of a rectangle whose length is twice the breadth and perimeter is 30 cm.
Find the perimeter of
square whose area is 16 cm².
in the shape of the rectangle whose dima​

Answer 1

Answer:

Step-by-step explanation: Area of a rectangle= l*b Perimeter of a rectangle= 2(l+b)

2(2x+x)= 30cm

= 4x+2x= 30cm

6x= 30cm

x= 5cm

length= 2x= 2*5cm= 10cm

breadth= x= 5cm

area = l*b

= 10cm*5cm

= 50cm²(area of the rectangle)

Answer 2

$\huge\underline{ \underline{ \texttt{GIVEN}}}$

• Perimeter of rectangle=30cm
• Length is double of Breadth of rectangle.
• Area of square=16cm²

$\huge\underline{ \underline{ \texttt{TO \: FIND}}}$

• Area of rectangle.
• Perimeter of square.

$\huge\underline{ \underline{ \texttt{SOLUTION}}}$

Let breadth of rectangle be x

then length of rectangle will be 2x

$\large\underline{ \boxed{ \sf \blue{ \bigstar Perimeter \: of \: rectangle \: = 2(L+B)}}}$

30cm=2(2x+x)

30cm=2(3x)

30cm=6x

$\sf \frac{30}{6} cm = x$

$\sf 5cm = x$

$\underline{\boxed{ \sf \large \purple{ \bigstar \: Area \: of \: rectangle =length×breadth}}}$

$\sf \implies2x \times x$

$\implies\sf2 {x}^{2}$

$\implies \sf (2 \times 5 \times 5)cm {}^{2}$

$\Large \red{\sf \implies5 0 {cm}^{2} }$

__________________________

$\large \underline{ \boxed{ \sf \pink{\bigstar Area \: of \: Square=Side²}}}$

$\sf16 {cm}^{2} = side {}^{2}$

$\sf \sqrt{16 {cm}^{2} } = side \: of \: square$

$\sf4cm = side \: of \: square$

$\large \underline{ \boxed{ \sf \green{ \bigstar Perimeter\:of\: square=4×side}}}$

$\sf4 \times side$

$\sf 4 \times 4cm$

$\Large\sf \fbox{ \orange{16cm = perimeter \: of \: square}}$