find the area of a rectangle whose length is twice the breadth and perimeter is 30 cm
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Answered by
13
Answer:
let the breadth be 'x'cm
then length will be '2x'cm
perimeter of rectangle is 30 cm
perimeter of rectangle=2(l+b)
30=2(2x+x)
30=2(3x)
30=6x
30/6=x
x=5 cm
therefore,
length is 2x=2x5=10cm
area of rectangle=(l x b)
=(10x5)
=50 sq.cm
hope it help you
Answered by
2
Answer:
Area of rectangle= 50cm^2
Step-by-step explanation:
Area of Rectangle= length×breadth
= 10×5
= 50cm^2
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