Question

find the area of a rectangle whose length is twice the breadth and perimeter is 30 cm

Answer 1

Hey!!!

Let the breadth of rectangle be "b"....

So, length of rectangle = 2b...

Also, perimeter = 30

i. e. 2(l + b) = 30

So, 3b is 15

So, b is 5 and l is 2*5 = 10.....


Area of rectangle

= l*b = 10 * 5

= 50 cm^2.....


Hope this helps.....

Feel free to ask any doubts

Answer 2

lxb=area
l=2b
l+b =30
2b+b =30
3b=30
b=10

sub b on l+b =30
l+10=30
l=20

area = l x b
20 x 10

= 200 cm²...

hence the area is 200 cm²

mark me as brainliest friend if it is helpful to you....