Question

Find the area of a rectangle whose length is V cm and breadth is K cm.​

Answer 1

${\large{\pmb{\sf{\underline{\maltese \: \: Understanding \: the \: question...}}}}}$

★ This question says that we have to find out the area of a rectangle whose length and breadth is V centimetres and K centimetres respectively.

Diagram of a rectangle is given below -

$\begin{gathered} \sf Length \: \: \: \: \: \: \: \: \: \: \: \\ \begin{gathered}\begin{gathered}\boxed{\begin{array}{}\bf { \red{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}\end{gathered}\end{gathered} \sf Breadth \end{gathered}$

Diagram of a rectangle according to this question is given below too -

$\begin{gathered} \sf V \: cm \: \: \: \: \: \: \: \: \: \: \: \\ \begin{gathered}\begin{gathered}\boxed{\begin{array}{}\bf { \red{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}\end{gathered}\end{gathered} \sf K \: cm \end{gathered}$

${\large{\pmb{\sf{\underline{\maltese \: \: Some \: formulas...}}}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Volume \: of \: cylinder \: = \: \pi r^{2}h}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Surface \: area \: of \: cylinder \: = \: 2 \pi rh + 2 \pi r^{2}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Lateral \: area \: of \: cylinder \: = \: 2 \pi rh}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Base \: area \: of \: cylinder \: = \: \pi r^{2}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Height \: of \: cylinder \: = \: \dfrac{v}{\pi r^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Radius \: of \: cylinder \: = \:\sqrt \dfrac{v}{\pi h}}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Perimeter \: of \: rectangle \: = 2(l+b)}}$

$\; \; \; \; \; \; \;{\sf{\leadsto Area \: of \: rectangle \: = L \times B}}$

${\large{\pmb{\sf{\underline{\maltese \: \: Given \; that...}}}}}$

★ Length of rectangle = V

★ Breadth of rectangle = K

${\large{\pmb{\sf{\underline{\maltese \: \: To \; find...}}}}}$

★ Area of rectangle

${\large{\pmb{\sf{\underline{\maltese \: \: Solution...}}}}}$

★ Area of rectangle = VK cm sq.

${\large{\pmb{\sf{\underline{\maltese \: \: Using \; Formula...}}}}}$

${\small{\underline{\boxed{\sf{Area \: of \: rectangle \: = Length \times Breadth}}}}}$

${\large{\pmb{\sf{\underline{\maltese \: \: Full \; Solution...}}}}}$

${\small{\underline{\boxed{\sf{\dashrightarrow Area \: of \: rectangle \: = Length \times Breadth}}}}}$

${\sf{\dashrightarrow Area \: of \: rectangle \: = Length \times Breadth}}$

${\sf{\dashrightarrow Area \: of \: rectangle \: = V \times K}}$

${\sf{\dashrightarrow Area \: of \: rectangle \: = VK \: cm^{2}}}$

${\underline{\pmb{\tt{\therefore \: VK \: cm^{2} \: is \: the \: area \: of \: rectangle}}}}$