Question

find the area of a rectangle whose one diagonal is 26 cm and length is 24 cm

Answer 1

Answer:

Area = $\huge\bold{240cm}^{2}$

Step-by-step explanation:

$\rightarrow$ Let's first find the breadth through Pythagoras theorem.

$\color{black}\boxed{\colorbox{saffron}{Hypotenuse = height+base}}$

Taking base(breadth) as 'x'

${26}^{2} = {24}^{2} + {x}^{2} \\ \\ = 676 = 576 + x \\ \\ = 676 - 576 = x \\ \\ = 100 = x \\ \\ {10}^{2} = {x}^{2} \\ \\ x = 10$

So, breadth = x=10cm

ㅤ

$\rightarrow$ Let's find the area of the rectangle now.

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

$24 \times 10 \\ \\ = {240cm}^{2}$

So, area is $\bold{240cm}^{2}$